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## Multiplying Two Selected 3-digit Numbers (middle Digit 1)

 Multiplying Two Selected 3-digit Numbers (middle Digit 1)Multiplying two selected 3-digit numbers   (middle digit 1) Select a 3-digit number with a middle digit of 1. Choose a multiplier with the same first two digits, whose third digit sums to 10 with the third digit of the first 3-digit number. The last two digits will be the product of the first digits: _ _ _ 0 X or _ _ _ _ X X. The third digit from the right will be 2: _ _ 2 _ _ or _ _ _ 2 _ _ . The next digit to the left will be 3 times the first digit of the number (keep carry): _ X _ _ _ or _ _ X _ _ _. The first digits will be the square of the first digit plus the carry: X _ _ _ _ or X X _ _ _ _. As you determine the digits in the answer from right to left, repeat them to yourself at each step until you have the whole answer.    Example: If the first number is 814, choose 816 as the second number (same first digits, second digits add to 10). 4 × 6 = 24 (multiply the first digits) - last two digits: _ _ _ _ 2 4. The third digit from the right is 2: _ _ 2 _ _ . 8 × 3 = 24 (the next digit to the left is 3 times the first digit (keep carry 2): _ _ 4 _ _ _ . 8 × 8 = 64; 64 + 2 = 66 ( the first digits are the square of the first digit plus the carry: 6 6 _ _ _ _. So 814 × 816 = 664224.    See the pattern? If the first number is 317, choose 313 as the multiplier (same first digits, second digits add to 10). 7 × 3 = 21 (multiply the first digits) - last two digits: _ _ _ _ 2 1. The third digit from the right is 2: _ _ 2 _ _ . 3 × 3 = 9 (the next digit to the left is 3 times the first digit (no carry): _ 9 _ _ _ . 3 × 3 = 9 ( the first digits are the square of the first digit: 9 _ _ _ _. So 317 × 313 = 99221.

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26 Sep, 2021, 03:28:09 AM